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If a student in the class, (Student A) wanted to determine how many standard deviations away from the mean their score was, they would need to calculate a z-score:

Z=((x- μ))/σ

In this formula, x is the given data point (Student A’s score) from the data set, µ is the mean, and σ is the standard deviation. Take the height of 80 inches as an example:

Z=((80-75))/9.3 Z=0.54

The equation indicates that Student A’s height of 80’’ was 0.54 standard deviations above the mean. This height falls into the 68% percent range of all scores and is slightly above average.

What’s useful about the z-score is it can be used to determine the probability of being above or below a given data point. For example, the z-score of 0.54 can be located along a z-table, which illustrates what percentage is under the distribution curve at any given point. The z-score of 0.54 corresponds to 0.7054 on the z-table. This means that student A is taller than 70.54% of the class and am shorter than 29.46% of the class. Another way to say this is that Student A had a 29.46% chance of being at least 80 inches tall.


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